Question

A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 × 10^-2 J. What is the magnitude of magnetic moment of the magnet?

Answer 1

Torque x = MB sinθ 4.5 × 10^-2 = M (0.25 sin 30°) Magnetic dipole moment, M = 0.36 J T^-1.