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Let \(f(x)=\frac{x-1}{x+1}\), then f(f(x)) is (a) \(\frac{1}{x}\) (b) \(-\frac{1}{x}\)

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Let \(f(x)=\frac{x-1}{x+1}\), then f(f(x)) is
(a) \(\frac{1}{x}\)
(b) \(-\frac{1}{x}\)
(c) \(\frac{1}{x+1}\)
(d) \(\frac{1}{x-1}\)

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Answer is (b) \(-\frac{1}{x}\)

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