Question

If f(x) = (ax² + b)³, then the function g such that f(g(x)) = g(f(x)) is given by
(a) $g(x)=\left(\frac{b-x^{1/3}}{a}\right)$
(b) $g(x)=\frac{1}{{(a{x}^2+b)}^3}$
(c) $g(x)={(a{x}^2+b)}^{1/3}$
(d) $g(x)={\left(\frac{x^{1/3}-b}{a}\right)}^{1/2}$

Answer 1

Correct option is d) $g(x)={\left(\frac{x^{1/3}-b}{a}\right)}^{1/2}$