Question

If f(x) = (ax² + b)³, then the function g such that f(g(x)) = g(f(x)) is given by
(a) \(g(x)=\left(\frac{b-x^{1 / 3}}{a}\right)\)
(b) \(g(x)=\frac{1}{\left(a x^{2}+b\right)^{3}}\)
(c) \(g(x)=\left(a x^{2}+b\right)^{1 / 3}\)
(d) \(g(x)=\left(\frac{x^{1 / 3}-b}{a}\right)^{1 / 2}\)

Answer 1

Correct option is d) \(g(x)=\left(\frac{x^{1 / 3}-b}{a}\right)^{1 / 2}\)