g=\(GM\over R^2\)
⇒\(M=\tfrac{gR^2}{G}\)
Acording to the given data , \(\tfrac{gB}{gA}=\tfrac{1}{2}\)
and \(\tfrac{{R_B}}{R_A}=2\)
![yes yes](https://doubtly.in/qa-plugin/q2a-wysiwyg-matheditor-master/plugins/smiley/images/thumbs_up.png)
⇒\(\tfrac{M_B}{M_A}=\tfrac{g_B}{g_A}( \tfrac {R_B}{R_A})^2\)
⇒\(\tfrac{M_B}{M_A}=\tfrac{1}{2}2^2\)
⇒\(M_B=2M_A\)
Video solution