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g=\(GM\over R^2\)

⇒\(M=\tfrac{gR^2}{G}\) 

Acording to the given data , \(\tfrac{gB}{gA}=\tfrac{1}{2}\)

and \(\tfrac{{R_B}}{R_A}=2\) 

yes

⇒\(\tfrac{M_B}{M_A}=\tfrac{g_B}{g_A}( \tfrac {R_B}{R_A})^2\)

⇒\(\tfrac{M_B}{M_A}=\tfrac{1}{2}2^2\)

⇒\(M_B=2M_A\)

Video solution

https://youtu.be/CRGIqlzFy08

Doubtly · 4 May 2021 Report
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