Question

The string of a guitar is 80 cm long and has a fundamental frequency of 112 Hz. If a guitarist wishes to produce a frequency of 160 Hz, where should the person press the string?

Answer 1

Given: L₁ = 80 cm n₁ = 112 Hz, n₂ =160 Hz

According to the law of length, n₁L₁ = n₂L₂.

 The vibrating length to produce the fundamental frequency of 160 Hz,

L₂ = \(\frac{n_1L_1}{n_2}\) = \(\frac{(112)(80)}{160}\)= 56 cm