Question

Find the change in length of a second’s pendulum, if the acceleration due to gravity at the place changes from 9.75 m/s² to 9.8 m/s².

Answer 1

Given : g₁ =9.75 m/s², g₂ = 9.8 m/s²

Length of a seconds pendulum, L = g/π²

∴ L₁ = g₁/π² = 9.75/9.872 = 0.9876 m and

∴ L₂ = g₂/π² = 9.8/9.872  = 0.9927 m

 The length of the seconds pendulum must be increased from 0.9876 m to 0.9927 m, i.e., (0.9927−0.9876) by 0.0051 m.