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Potential energy of a particle performing linear S.H.M is 0.1 π2 x2 joule. If mass of the particle is 20 g,

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Potential energy of a particle performing linear S.H.M is 0.1 π2 x2 joule. If mass of the particle is 20 g, find the frequency of S.H.M.

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Given : PE = 0.1π2x2 J, m = 20 g = 2 X 10-2 kg

PE = ½ mw2x2 = ½m(4π2η2)x2 = 0.1π2x2

∴ 2mη2 = 0.1

∴ η2 =  0.1/[2(2 X 10-2)]= 2.5

∴ The frequency of SHM is

η = \(\sqrt{2.5}\) = 1.581 Hz

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