(a) λmax = 700 nm = 700×10-9 m,
(b) λmax = 3 cm = 3×10-2 m,
(c) λmax = 3 m
b = 2.897 × 10-3 m K
(a)
T= b/λmax = (2.897 × 10-3 )/ (700×10-9)
= 4138 K is the required temperature
(b)
T= b/λmax = (2.897 × 10-3 )/ (3×10-2)
= 9.66×10-2 K is the required temperature
(c)
T= b/λmax = (2.897 × 10-3 )/ (3)
= 9.66×10-4 K is the required temperature