(i) We know that,
Molar mass= sum of constituent atomic masses
Molar mass of NaCl= 23 + 35.5 = 58.5 g/mol
Number of moles of a substance= \(\frac{\text{Molar mass of substance in grams}}{\text{Molecular mass of the substance}}\)
0.2=\(\frac{x}{58.5}\)
x = 0.2×58.5 = 11.7g
We need, 11.7 g of NaCl for obtaining 0.2 moles of NaCl.
(ii) Molar mass of MgO= 24 + 16 = 40 g/mol
Number of moles of a substance= \(\frac{\text{Molar mass of substance in grams}}{\text{Molecular mass of the substance}}\)
0.2=\(\frac{x}{40}\)
x = 0.2×40 = 8g
We need, 8 g of MgO for obtaining 0.2 moles of MgO.
(iii) Molar mass of CaCO3= 40 + 12 + 3 (16) = 100 g/mol
Number of moles of a substance= \(\frac{\text{Molar mass of substance in grams}}{\text{Molecular mass of the substance}}\)
0.2=\(\frac{x}{100}\)
x =0.2×100= 20 g
We need, 20 g of CaCO3 for obtaining 0.2 moles of CaCO3.