Question

Pravin has applied a force of 100 N on an object, at an angle of 60⁰ to the horizontal. The object gets displaced in the horizontal direction and 400 J work is done. What is the displacement of the object?

(cos 60⁰ = 1/2)

Answer 1

Given here is θ=60⁰ and F=100N, while W= 400J , SO s=?

Take the equation W = F s Cos θ

Replace with values 400= 100 × s × ½

Hence, 400 / 100 = ½ × s

4 × 2 = s

Therefore, s=8 m.

The displacement of the object = 8m.