Ask a Question

The oxidation state of Fe in the brown ring complex [Fe(H2O)5NO]SO4 is:(a) + 1 (b) + 2 (c) + 3 (d) + 4

0 votes
239 views
in random by (98.9k points)
reopened by

The oxidation state of Fe in the brown ring complex [Fe(H2O)5NO]SO4 is: 

(a) + 1
(b) + 2
(c) + 3
(d) + 4

1 Answer

0 votes
by (98.9k points)
selected by
 
Best answer

Corret option is a) +1

Explaination ::
[Fe(H2O)5NO]SO4 \(\rightarrow ([Fe(H_2O)_5NO] )^{+2}+(SO_4)^{-2}\) 

\((fe^+)^{+1} =+2\)

charge on fe= +1

Related questions

0 votes
1 answer 215 views
As per IUPAC nomenclature, the name of the complex [Co (H2O)4(NH3 )2]C13 is
asked Apr 9, 2021 in random by Doubtly (98.9k points)
0 votes
1 answer 195 views
The number of enantiomer in a glucose molecule is (a) 16 (b) 12 (c) 4 (d) 9
asked Apr 9, 2021 in random by Doubtly (98.9k points)

Doubtly is an online community for engineering students, offering:

  • Free viva questions PDFs
  • Previous year question papers (PYQs)
  • Academic doubt solutions
  • Expert-guided solutions

Get the pro version for free by logging in!

Most popular tags

jeemain geography-10th engineering physics semester 5 web computing

5.7k questions

5.1k answers

108 comments

557 users

Doubtly
...