Question

Find out  the number  of  enantiomer, meso isomer  and total number of  optical isomers for  the following  compound 

(a) 3,2,4

(b)  0,2,3

(c) 4,0,4

(d)  0,2,2 

Answer 1

Correct option is C) 4,0,4

explaination :

Number of enantiomer = 2n (n is the number of chiral carbon )

Number of meso isomer = 0

Total number of optical isomer= 2ⁿ + 0 

Solving

Chiral carbon, n= 2

So Number of enantiomer = 2ⁿ = 2² = 4

Number of meso isomer = 0

Total number of optical isomer= 2ⁿ + 0 = 4+0= 4