Question

What is the angular momentum of the electron in the third Bohr orbit in the hydrogen atom? (h/2π =1.055 × 10^-34 kg m² / s)

a) 3.165 × 10^-34 kg m² / s

b) 3.165 × 10³⁴ kg m² / s

c) 3.165 × 10^-24 kg m² / s

d) 3.165 × 10²⁴ kg m² / s

 

Answer 1

 

Angular momentum of an electron in the nth Bohr orbit of hydrogen atom L=\(nh \over 2\pi\)

For n=3

\(L={3h\over 2\pi}\)

\(L={3\times1.055\times10^{-34}}\)

L=3.165 \(\times 10^{-34} Kg m^2/ s\)

a)option is correct