0 votes
123 views
in maths by (98.9k points)
reopened by

Prove.

\(\sec^2 a + cosec ^ 2 a = Sec^2 a. Cosec^2 a\)

1 Answer

0 votes
by (98.9k points)
selected by
 
Best answer

Proof ::

LHS = sec2 A + cosec2 A 

\(={1\over(cos^2A)}+{1\over(sin^2A)}={(sin^2A+cos^2A)\over(cos^2A sin^2A)}\) 

\(={1\over(cos^2A sin^2A)}=sec^2A cosec^2A=RHS\)

Related questions

0 votes
1 answer 180 views
+1 vote
1 answer 397 views
+1 vote
1 answer 250 views

Doubtly is an online community for engineering students, offering:

  • Free viva questions PDFs
  • Previous year question papers (PYQs)
  • Academic doubt solutions
  • Expert-guided solutions

Get the pro version for free by logging in!

5.7k questions

5.1k answers

108 comments

557 users

...