0 votes
327 views
in Chapter 1: Gravitation by
reshown by
by (98.9k points)
edited
To find out the weights of five friends on the moon and Mars, we need to first understand how the weight of an object changes in different gravitational environments.

On the moon, the gravitational acceleration is about 1/6th of the Earth's gravity, which means objects weigh only 1/6th of their weight on Earth. On the other hand, Mars has a gravitational acceleration of about 0.38 times that of Earth, which means objects weigh about 0.38 times their weight on Earth.

Let's assume the weights of our five friends on Earth are as follows:

Friend 1: 70 kg
Friend 2: 80 kg
Friend 3: 60 kg
Friend 4: 90 kg
Friend 5: 75 kg
Now, let's calculate their weights on the moon and Mars using the following formulas:

Weight on the moon = Weight on Earth / 6
Weight on Mars = Weight on Earth * 0.38

Using these formulas, we get the following weights:

Friend 1:

Weight on the moon = 70 / 6 = 11.67 kg
Weight on Mars = 70 * 0.38 = 26.6 kg

Friend 2:

Weight on the moon = 80 / 6 = 13.33 kg
Weight on Mars = 80 * 0.38 = 30.4 kg

Friend 3:

Weight on the moon = 60 / 6 = 10 kg
Weight on Mars = 60 * 0.38 = 22.8 kg

Friend 4:

Weight on the moon = 90 / 6 = 15 kg
Weight on Mars = 90 * 0.38 = 34.2 kg

Friend 5:

Weight on the moon = 75 / 6 = 12.5 kg
Weight on Mars = 75 * 0.38 = 28.5 kg

Therefore, the weights of our five friends on the moon and Mars are as follows:

On the moon:

Friend 1: 11.67 kg
Friend 2: 13.33 kg
Friend 3: 10 kg
Friend 4: 15 kg
Friend 5: 12.5 kg
On Mars:

Friend 1: 26.6 kg
Friend 2: 30.4 kg
Friend 3: 22.8 kg
Friend 4: 34.2 kg
Friend 5: 28.5 kg

1 Answer

0 votes
by (98.9k points)
selected by
 
Best answer

Person on Mars would weigh 37.83% its weight on earth.


image

Related questions

Doubtly is an online community for engineering students, offering:

  • Free viva questions PDFs
  • Previous year question papers (PYQs)
  • Academic doubt solutions
  • Expert-guided solutions

Get the pro version for free by logging in!

5.7k questions

5.1k answers

108 comments

535 users

...