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If f(x) = ∫t(sinx - sint)dt for t ∈ [0, x] then (A) f'''(x) + f''(x)

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If f(x) = ∫t(sinx - sint)dt for t ∈ [0, x] then

(A) f'''(x) + f''(x) = sinx

(B)f'''(x) + f''(x) - f'(x) = cosx

(C) f'''(x) + f'(x) = cosx - 2xsinx

(D) f'''(x) - f''(x) = cosx - 2xsinx

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option d is correct (D) f'''(x) - f''(x) = cosx - 2xsinx

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