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\(\triangle V =10-5=5 \space litre=5×10^3 m^3\)
\(Q=400J \space ,\space \space P=1atm =1.013×10^{-5} pa\) W=p.dV=\(1.013×10^5 ×5 ×10^{-3}\)
=506.5 J
\(\triangle U=Q-W\) =400-506.5 J
=-106.5 J
\(|\triangle U|=106.5 J\)
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