Question

A pulley of radius 2 m is rotated about its axis by a force F =20t-5t² newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kgm² , the number of rotations made by the pulley before its direction of motion it reversed,

Options:

(a) more than 6 but less than 9

(b) more than 9

(c) less than 3

(d) more than 3 but less than 6

Answer 1

Torque is given by τ = FR

Or α = FR/I

Given

F =20t – 5t2 R = 2m,

I = 10 kgm2

α = \((20t-5t^2)\times2\over 10\)

α = 4t – t 2

 

\(\omega=\int_t^2\alpha dt=2t^2-t^3/3\)

at \(\omega =0 =2t^2-t^3/3 \)

\(t^3=6t^2\)

\(t=6\)

\(\theta=\int_0^6 \omega dt=\int_0^6(2t^2-t^3/3)dt\)

\(\theta={ 36\over2\pi} <6\)

Hence, your answer should be (d) more than 3 but less than 6