Question

If both FeX₂ & FeY₃ are found to exist, X & Y can be : 

 (1) X = F, Cl, Br, I    ::   Y = F, Cl, Br 

 (2) X = Cl, Br, I       ::  Y = F, Cl, Br, I

 (3) X = F, Cl, Br      :: Y = Cl, Br, I

 (4) X = F, Cl, Br, I   :: Y = F, Cl, Br, I

Answer 1

(1) X = F, Cl, Br, I :: Y = F, Cl, Br  is the correct option 

Explaination::

FeI₃ does not exist as I^– reduces Fe³⁺ to Fe²⁺. 2Fe³⁺ + 2I – → 2Fe²⁺ + I₂.