Question

In a hydraulic lift, the input piston had surface area 30 cm² and the output piston has surface area of 1500 cm². If a force of 25 N is applied to the input piston, calculate weight on output piston. 

Answer 1

Correct answer = 1250 N

Explaination::

Given : A₁ = 30 cm² = 3×10^-3 m² , A₂ = 1500 cm² = 0.15 m² F₁=25 N

By Pascal’s law

\(\frac{F1}{A1}=\frac{F2}{A2}\)

∴The force on the output piston,

\(F2=F1(\frac{A2}{A1})\)

= \((25)\frac{0.15}{3×10^3}  \)=25 × 50=1250 N

Weight on output piston = 1250 N