Question

Find the pressure 200 m below the surface of the ocean if pressure on the free surface of liquid is one atmosphere. (Density of sea water = 1060 kg/m³)

Answer 1

Correct Answer=  21.789×10⁵  N/m² 

Explaination::

Given : h=200 m, ρ=1060 kg/m³ p₀ = 1.013×10⁵ Pa, g = 9.8 m/s²

Absolute pressure,

Solution::

P=p₀+hρg

= (1.013×10⁵ )+(200×1060×9.8)

= (1.013×10⁵ )+(20.776×10⁵)

= 21.789×10⁵  N/m²